What would be the highest value of X in the given equation:
1X9 + 1Y7 + 2Z8 = 424
Given:
The equation is 1X9 + 1Y7 + 2Z8 = 424
Solution:
We express the numbers in terms of the digits:
1X9 = 100 + 10X + 9
1Y7 = 100 + 10Y + 7
2Z8 = 200 + 10Z + 8.
The equation becomes:
(100 + 10X + 9) + (100 + 10Y + 7) + (200 + 10Z + 8) = 424.
400 + 10(X + Y + Z) + 24 = 424
424 + 10(X + Y + Z) = 424.
10(X + Y + Z) = 0
X + Y + Z = 0.
For the sum X + Y + Z = 0, the only solution is X = 0, Y = 0, and Z = 0.
Thus, the highest value of X is 0.
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