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Find the value of x in the equation 23x=16x+2.2^{3x} = 16^{x+2}.23x=16x+2.​​
Question

Find the value of x in the equation 23x=16x+2.2^{3x} = 16^{x+2}.​​

A.

5

B.

7

C.

8

D.

-8

Correct option is D

Given:

23x=16x+22^{3x} = 16^{x+2}

Formula used:

am=an,a^m = a^n,

Then m = n

Solution:

23x=16x+22^{3x} = 16^{x+2}

23x=24×(x+2)2^{3x} = 2^{4\times({x+2})}

23x=24x+82^{3x} = 2^{4x+8}

3x = 4x + 8

4x - 3x = -8

x = -8

Thus, the correct answer is (d).

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