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    Find the value of x in the equation 23x=16x+2.2^{3x} = 16^{x+2}.23x=16x+2.​​
    Question

    Find the value of x in the equation 23x=16x+2.2^{3x} = 16^{x+2}.​​

    A.

    5

    B.

    7

    C.

    8

    D.

    -8

    Correct option is D

    Given:

    23x=16x+22^{3x} = 16^{x+2}

    Formula used:

    am=an,a^m = a^n,

    Then m = n

    Solution:

    23x=16x+22^{3x} = 16^{x+2}

    23x=24×(x+2)2^{3x} = 2^{4\times({x+2})}

    23x=24x+82^{3x} = 2^{4x+8}

    3x = 4x + 8

    4x - 3x = -8

    x = -8

    Thus, the correct answer is (d).

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