What time (in seconds) is required for a 496 m long train to cross a 664 m long tunnel, if the train travels at a speed of 18 km/h?

Correct option is A

Given:

Length of train = 496 m, Length of tunnel = 664 m, Speed of train = 18 km/h
Formula Used:

Time =$$\frac{\text{Distance}}{\text{Speed}}$$​​
Solution:
Speed =$$18 {\text{km/h}} \times \frac{1000 \, \text{m}}{1 \, \text{km}} \times \frac{1 \, \text{h}}{3600 \, \text{s}} = 5 \text{m/s}$$​​
Total distance = Length of train + Length of tunnel = 496 m + 664 m = 1160 m
Calculate the time required to cross the tunnel:
Time = $$\frac{\text{Distance}}{\text{Speed}}$$​ =$$\frac{1160 m }{ 5 m/s } = 232 sec$$