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    What time (in seconds) is required for a 284 m long train to cross a 676 m long tunnel, if the train travels at a speed of 18 km/h?
    Question

    What time (in seconds) is required for a 284 m long train to cross a 676 m long tunnel, if the train travels at a speed of 18 km/h?

    A.

    195

    B.

    193

    C.

    192

    D.

    188

    Correct option is C

    Given:

    Length of train = 284 m, Length of tunnel = 676 m, Speed of train = 18 km/h
    Formula Used:

    Time =DistanceSpeed\frac{\text{Distance}}{\text{Speed}} ​​
    Solution:
    Speed =18km/h×1000 m1 km×1 h3600 s=5m/s18 {\text{km/h}} \times \frac{1000 \, \text{m}}{1 \, \text{km}} \times \frac{1 \, \text{h}}{3600 \, \text{s}} = 5 \text{m/s}​​
    Total distance = Length of train + Length of tunnel = 284 m + 676 m = 960 m
    Calculate the time required to cross the tunnel:
    Time = DistanceSpeed\frac{\text{Distance}}{\text{Speed}} ​ =960m5m/s=192sec\frac{960 m }{ 5 m/s } = 192 sec

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