What is the value of x, if:  -3×√196+√x = 8×3-2 ?

Correct option is A

Given:

$$-3×\sqrt{196} + \sqrt{x} = 8×3 - 2$$​

Solution: 

$$-3×\sqrt{196} + \sqrt{x} = 24 - 2$$​

$$-3 × 14 + \sqrt{x} = 22 \\ \ \\ \implies -42 + \sqrt{x} = 22 \\ \ \\ \implies \sqrt{x} = 22+42\\ \ \\ \implies \sqrt{x} = 64\\ \ \\ \implies \ {x} = 4096$$​