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If 2352=2x×3y×7z2352 = 2^x \times 3^y \times 7^z \\2352=2x×3y×7z​, then the value of x+y+zx + y + zx+y+z​ is
Question

If 2352=2x×3y×7z2352 = 2^x \times 3^y \times 7^z \\​, then the value of x+y+zx + y + z​ is

A.

5

B.

7

C.

8

D.

9

Correct option is B

Given:
2352=2x×3y×7z2352 = 2^x \times 3^y \times 7^z \\​​
Solution:
Prime factorization of 2352:
2352÷2=11761176÷2=588588÷2=294294÷2=147147÷3=4949÷7=77÷7=12352 \div 2 = 1176 \\1176 \div 2 = 588 \\588 \div 2 = 294 \\294 \div 2 = 147 \\147 \div 3 = 49 \\49 \div 7 = 7 \\7 \div 7 = 1 \\​​
=>2352=24×31×72=>x=4,y=1,z=2x+y+z=4+1+2=7\Rightarrow 2352 = 2^4 \times 3^1 \times 7^2 \\\Rightarrow x = 4, \quad y = 1, \quad z = 2 \\x + y + z = 4 + 1 + 2 = 7 \\​​
Correct answer is (b) 7.

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