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Find the value of K for which equation x – Ky = 2, 3x + 2y = 5 has unique solution.
Question

Find the value of K for which equation x – Ky = 2, 3x + 2y = 5 has unique solution.

A.

​K≠−23K \ne -\frac{2}{3} \quad​​

B.

​K=23K = \frac{2}{3} \quad​​

C.

​K≠23K \ne \frac{2}{3} \quad​​

D.

​K=−23 K = -\frac{2}{3} \\[12pt]​​

Correct option is A

Given equations:
​x−Ky=2=>a1=1, b1=−K3x+2y=5=>a2=3, b2=2x - Ky = 2 \quad \Rightarrow a_1 = 1,\ b_1 = -K \\3x + 2y = 5 \quad \Rightarrow a_2 = 3,\ b_2 = 2 \\[8pt]​​
For unique solution:
​a1a2≠b1b2=>13≠−K2\frac{a_1}{a_2} \ne \frac{b_1}{b_2} \Rightarrow \frac{1}{3} \ne \frac{-K}{2} \\​​
Cross-multiplying: 2≠−3K=>K≠−232 \ne -3K \Rightarrow K \ne -\frac{2}{3} \\[10pt]​​
Correct answer is (a) K≠−23K \ne -\frac{2}{3}​​​​

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