Given: 4345k423 is divisible by 9
Formula Used: A number is divisible by 9 if the sum of its digits is divisible by 9.
Solution:
Sum of known digits: 4 + 3 + 4 + 5 + 4 + 2 + 3 = 25
Total sum with k: 25 + k
We need 25 + k to be divisible by 9. Try values from 0 to 9:
- k = 0 → 25 + 0 = 25
- k = 1 → 26
- k = 2 → 27 (Divisible by 9)
- k = 3 → 28
- k = 4 → 29
Only k = 2 satisfies the condition.
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