Write the smallest 5-digit number using digits 2, 3, 5, 8 and 9 which is divisible by 9

Correct option is A

Given:

Digits given: 2, 3, 5, 8, 9 (each to be used once)

Form the smallest 5-digit number divisible by 9

Solution:
Sum of given digits:

2 + 3 + 5 + 8 + 9 = 27

Since 27 is divisible by 9, any arrangement of these digits will be divisible by 9.

To get the smallest 5-digit number, arrange the digits in ascending order:

2, 3, 5, 8, 9

Smallest number formed = 23589