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    Which of the following number is divisible by both 3 and 8?
    Question

    Which of the following number is divisible by both 3 and 8?

    A.

    4260

    B.

    4016

    C.

    4128

    D.

    3412

    Correct option is C

    Given:
    Options: 4260, 4016, 4128, 3412
    Number must be divisible by both 3 and 8.
    Formula Used:
    Divisibility by 3: Sum of digits is divisible by 3.
    Divisibility by 8: Last three digits form a number divisible by 8.
    Solution:
    Check option A (4260):
    Sum of digits = 4 + 2 + 6 + 0 = 12 (Divisible by 3).
    Last three digits = 260. 2608 \frac{260}{8}​ = 32.5 (Not divisible by 8).
    Check option B (4016):
    Sum of digits = 4 + 0 + 1 + 6 = 11 (Not divisible by 3).
    Check option C (4128):
    Sum of digits = 4 + 1 + 2 + 8 = 15 (Divisible by 3).
    Last three digits = 128.  1288\frac{128}{8}​ = 16 (Divisible by 8).
    Since 4128 satisfies both conditions, it is the correct number.
    Final Answer
    So the correct answer is (c)

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