The greatest number that divides 63, 75 and 93 leaving remainder 3 in each case is:
Given:
The greatest number that divides 63, 75, and 93, leaving remainder 3 in each case.
Solution:
Subtract the remainder 3 from each number:
63 - 3 = 60, 75 - 3 = 72, 93 - 3 = 90
Now , HCF(60,72,90) = 6
Thus, 6 is the greatest number which divides 63, 75, and 93, leaving remainder 3 in each case.
English
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60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishThe greatest number that divides 63, 75 and 93 leaving remainder 3 in each case is:
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