What is the area of a rhombus, whose sides are 25 cm and one of the diagonals is 14 cm?

Correct option is C

Given:
Sides = 25 cm, one diagonal = 14 cm.

Formula Used: 

Area of rhombus = $$\frac{1}{2} \times \text{diagonal}_1 \times \text{diagonal}_2$$  

Relation between diagonal and side of the rhombus;

$$d_1^2 + d_2^2 = 4 \times \text{side}^2$$ 

where d₁ and d₂ are diagonals
Solution: 

Putting the values; 

$$14^2 + d_2^2 = 4 \times 25^2$$ 

​$$196 + d_2^2 = 2500$$ 

​$$d_2^2 = 2304, \\ \implies d_2 = 48$$ 

Now, 

Area = $$\frac{1}{2} \times 14 \times 48 = 336 \, \text{cm}^2$$ 

Thus, the Area of the rhombus is 336 cm²​