A hall is 42 m long and its breadth is 1/3 of length. Its floor is to be covered with tiles of 50 cm length and 30 cm breadth. Required number of tiles will be

Correct option is C

Given:

Length of hall = 42 m

Breadth of hall = $$\frac{1}{3}$$​ of length

Size of one tile = 50 cm × 30 cm

Find required number of tiles

Formula Used:

Area = Length × Breadth

Number of tiles = (Area of floor) ÷ (Area of one tile)

Solution:

Breadth of hall:

$$\frac{1}{3} \times 42$$​ = 14 m

Area of hall = $$42 \times 14 = 588 \text{ m}^2$$​

Convert tile dimensions into metres:

​$$50 \text{ cm} = 0.5 \text{ m}, \quad 30 \text{ cm} = 0.3 \text{ m}$$​​

Area of one tile = $$0.5 \times 0.3 = 0.15 \text{ m}^2$$​

Number of tiles required = $$\frac{588}{0.15}$$​ = 3920 tiles