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Two triangles ABC and DEF are similar. The smallest side of ABC is equal to 15 units. If the sides of ABC are in the ratio 3 ∶ 4 ∶ 5, and the area of
Question

Two triangles ABC and DEF are similar. The smallest side of ABC is equal to 15 units. If the sides of ABC are in the ratio 3 ∶ 4 ∶ 5, and the area of DEF is half of the area of ABC, then what is the largest side of DEF (in units)?

A.

252\sqrt 2​​

B.

253\sqrt 3

C.

253\frac {25}{\sqrt3}

D.

252\frac {25}{\sqrt2}

Correct option is D

Given:
∆ABC ~ ∆ DEF
Ratio of ar(DEF)ar(ABC)=12\text{Ratio of } \frac{\text{ar}(\triangle DEF)}{\text{ar}(\triangle ABC)} = \frac{1}{2}​​
Smallest side of ABC=15 units
Sides of ABC are in the ratio 3∶4 ∶ 5
Formula Used:
ar(ABC)ar(DEF)=AB2DE2=BC2EF2=AC2DF2\frac{\text{ar}(\triangle ABC)}{\text{ar}(\triangle DEF)} = \frac{AB^2}{DE^2} = \frac{BC^2}{EF^2} = \frac{AC^2}{DF^2}​​
Solution:
Let AB be smallest side of ∆ABC and AC be largest.
Then,
ar(DEF)ar(ABC)=DE2AB212=DE215212=DE15DE=152\frac{\text{ar}(\triangle DEF)}{\text{ar}(\triangle ABC)} = \frac{DE^2}{AB^2}\\\frac{1}{2} = \frac{DE^2}{15^2}\\\sqrt{\frac{1}{2}} = \frac{DE}{15}\\DE = \frac{15}{\sqrt{2}}\\​​
If sides of ABC are in the ratio 3∶4 ∶ 5then sides of ∆ DEF are also in the same ratio.
Hence DE: EF: DF = 3:4:5
DEDF=35DE×53=DF152×53=252\frac{DE}{DF} = \frac{3}{5}\\DE \times \frac{5}{3} = DF\\\frac{15}{\sqrt{2}} \times \frac{5}{3} = \frac{25}{\sqrt{2}}\\​​

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