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    If ΔABC ≅ ΔPQR, such that ∠ABC = 77°, ∠BCA = (x − y)°, AC = 48 cm, ∠PQR = (3x − 4)°, PR = x + 3y, then find the value of ∠QRP.​
    Question

    If ΔABC ≅ ΔPQR, such that ∠ABC = 77°, ∠BCA = (x − y)°, AC = 48 cm, ∠PQR = (3x − 4)°, PR = x + 3y, then find the value of ∠QRP.​

    A.

    28°

    B.

    32°

    C.

    23°

    D.

    20°

    Correct option is D

    Given:

    △ABC ≅ △PQR

    ∠ABC = 77

    ∠BCA = (x − y)

    AC = 48 cm

    ∠PQR = (3x − 4)

    PR = x + 3y

    Concept Used:

    In congruent triangles, corresponding angles are equal and corresponding sides are equal.

    Solution: 

    Corresponding angles: ∠ABC = ∠PQR,  ∠BCA = ∠QRP

    Corresponding sides: AC = PR

    From angle correspondence:

    ∠ABC = ∠PQR

    77∘ = 3x − 4

    3x = 81

    x = 27

    From side correspondence:

    AC = PR

    48 = x + 3y

    3y = 21

    y = 7

    Now, using the corresponding angles:

    ∠BCA = ∠QRP

    ∠QRP = x − y = 27 − 7 = 20

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