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If ΔABC ≅ ΔPQR, such that ∠ABC = 77°, ∠BCA = (x − y)°, AC = 48 cm, ∠PQR = (3x − 4)°, PR = x + 3y, then find the value of ∠QRP.​
Question

If ΔABC ≅ ΔPQR, such that ∠ABC = 77°, ∠BCA = (x − y)°, AC = 48 cm, ∠PQR = (3x − 4)°, PR = x + 3y, then find the value of ∠QRP.​

A.

28°

B.

32°

C.

23°

D.

20°

Correct option is D

Given:

△ABC ≅ △PQR

∠ABC = 77

∠BCA = (x − y)

AC = 48 cm

∠PQR = (3x − 4)

PR = x + 3y

Concept Used:

In congruent triangles, corresponding angles are equal and corresponding sides are equal.

Solution: 

Corresponding angles: ∠ABC = ∠PQR,  ∠BCA = ∠QRP

Corresponding sides: AC = PR

From angle correspondence:

∠ABC = ∠PQR

77∘ = 3x − 4

3x = 81

x = 27

From side correspondence:

AC = PR

48 = x + 3y

3y = 21

y = 7

Now, using the corresponding angles:

∠BCA = ∠QRP

∠QRP = x − y = 27 − 7 = 20

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