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    Two trains having lengths of 340 m and 360 m are running at speeds of 80 km/h and 90 km/h, respectively, in the same direction. The time taken (in min
    Question

    Two trains having lengths of 340 m and 360 m are running at speeds of 80 km/h and 90 km/h, respectively, in the same direction. The time taken (in minutes) by the faster train, coming from behind, to completely cross the other train is:

    A.

    7

    B.

    4.2

    C.

    3.7

    D.

    6

    Correct option is B

    Given:

    Length of first train = 340 m

    Length of second train = 360 m

    Speed of first train = 80 km/h

    Speed of second train = 90 km/h

    Concept Used:

    Relative Speed=Speed of faster trainSpeed of slower train Time=Sum of train lengthsRelative speed\text{Relative Speed} = \text{Speed of faster train} - \text{Speed of slower train}\\ \ \\\text{Time} = \frac{\text{Sum of train lengths}}{\text{Relative speed}}

    Solution:

    Length of both train = 360 + 340 = 700  

    Both train, same direction that's why Difference = 90 - 80 = 10 km/hr 

    ​Total = Total Distance Total time×185\frac{\text{Total Distance }}{\text{Total time}}\times\frac{18}5 ​    

    70010×185=252sec\frac{700}{10}\times\frac{18}5 = 252 sec

    In 60 sec = 1 min
    252 sec = 160×252=4.2min\frac{1}{60}\times 252 = 4.2 \text{min}

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