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Two trains having lengths of 340 m and 360 m are running at speeds of 80 km/h and 90 km/h, respectively, in the same direction. The time taken (in min
Question

Two trains having lengths of 340 m and 360 m are running at speeds of 80 km/h and 90 km/h, respectively, in the same direction. The time taken (in minutes) by the faster train, coming from behind, to completely cross the other train is:

A.

7

B.

4.2

C.

3.7

D.

6

Correct option is B

Given:

Length of first train = 340 m

Length of second train = 360 m

Speed of first train = 80 km/h

Speed of second train = 90 km/h

Concept Used:

Relative Speed=Speed of faster trainSpeed of slower train Time=Sum of train lengthsRelative speed\text{Relative Speed} = \text{Speed of faster train} - \text{Speed of slower train}\\ \ \\\text{Time} = \frac{\text{Sum of train lengths}}{\text{Relative speed}}

Solution:

Length of both train = 360 + 340 = 700  

Both train, same direction that's why Difference = 90 - 80 = 10 km/hr 

​Total = Total Distance Total time×185\frac{\text{Total Distance }}{\text{Total time}}\times\frac{18}5 ​    

70010×185=252sec\frac{700}{10}\times\frac{18}5 = 252 sec

In 60 sec = 1 min
252 sec = 160×252=4.2min\frac{1}{60}\times 252 = 4.2 \text{min}

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