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    Two trains C and D starts moving from stations R and S respectively towards each other. Trains take 4 hours 16 minutes and 3 hours 45 minutes to reach
    Question

    Two trains C and D starts moving from stations R and S respectively towards each other. Trains take 4 hours 16 minutes and 3 hours 45 minutes to reach S and R respectively after they meet each other. If the speed of train C is 60 km/hr, then what is the speed of the train D?

    A.

    64 km/hr

    B.

    72 km/hr

    C.

    48 km/hr

    D.

    56 km/hr

    Correct option is A

    Given:
    After meeting:
    Train C takes 4 hours 16 minutes to reach station S
    Train D takes 3 hours 45 minutes to reach station R
    Speed of Train C = 60 km/hr
    We need to find the speed of Train D

    Formula Used:

    After meeting, the ratio of speeds is equal to the square root of the inverse ratio of time taken: 

    SCSD=TDTC\frac{S_C}{S_D} = \sqrt{\frac{T_D}{T_C}}

    Calculation:
    Convert times into hours:
    4 hours 16 minutes = 4 + 16/60 = 64/15 hours
    3 hours 45 minutes = 3 + 45/60 = 15/4 hours

    Now apply the formula:​​

    60SD=15/464/15=15×154×64=225256=1516\frac{60}{S_D} = \sqrt{\frac{15/4}{64/15}} = \sqrt{\frac{15 \times 15}{4 \times 64}} = \sqrt{\frac{225}{256}} = \frac{15}{16}

    60SD=1516\frac{60}{S_D} = \frac{15}{16}

    SD=60×1615=96015=64 km/hrS_D = \frac{60 \times 16}{15} = \frac{960}{15} = 64 \text{ km/hr}​​​​

    Final Answer: The speed of Train D is 64 km/hr

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