Two men start walking together to a certain destination, one at the speed of 6 km/h, and the other at 7.5 km/h. The latter arrives 1 h 4 min before the former. The distance covered is:

Correct option is C

Given:

Speed of first man = 6 km/h

Speed of second man = 7.5 km/h

First man arrives 1h 4 min before then Second man.

Formula Used:

Speed = $$\frac{{Distance }}{{Time}}$$​​

Solution 

Let the distance = x 

According to the question 

$$\frac{x}{6}- \frac{x}{7.5} = 1h \ 4 \ min$$  

​$$x\frac{(7.5 - 6) }{45} = \frac{16}{15}$$   

x =  $$\frac{48}{1.5} = 32 km$$​​

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