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Train X crosses train Y while running in opposite directions in 10 seconds, and the lengths of train X and train Y are ‘d’ meters and ‘d + 40’ meters,
Question

Train X crosses train Y while running in opposite directions in 10 seconds, and the lengths of train X and train Y are ‘d’ meters and ‘d + 40’ meters, respectively. If the speeds of train X and train Y are 108 km/h and 126 km/h, respectively, then find the value of d.

A.

300

B.

305

C.

290

D.

245

E.

260

Correct option is B

Information Given:
Train X crosses another train Y in 10 seconds.
The lengths of train X and train Y are ‘d’ meters and ‘d + 40’ meters respectively.
The speeds of train X and train Y are 108 km/h and 126 km/h respectively
Formulas Used:
Time: Distance/Speed
Basic Explanation:
ATQ,
d+d+40518×(108+126)=10\frac{d + d + 40}{\frac{5}{18} \times (108 + 126)} = 10

2d+4065=10\frac{2d + 40}{65} = 10
2d + 40 =650
d = 305

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