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    Train X crosses train Y while running in opposite directions in 10 seconds, and the lengths of train X and train Y are ‘d’ meters and ‘d + 40’ meters,
    Question

    Train X crosses train Y while running in opposite directions in 10 seconds, and the lengths of train X and train Y are ‘d’ meters and ‘d + 40’ meters, respectively. If the speeds of train X and train Y are 108 km/h and 126 km/h, respectively, then find the value of d.

    A.

    300

    B.

    305

    C.

    290

    D.

    245

    E.

    260

    Correct option is B

    Information Given:
    Train X crosses another train Y in 10 seconds.
    The lengths of train X and train Y are ‘d’ meters and ‘d + 40’ meters respectively.
    The speeds of train X and train Y are 108 km/h and 126 km/h respectively
    Formulas Used:
    Time: Distance/Speed
    Basic Explanation:
    ATQ,
    d+d+40518×(108+126)=10\frac{d + d + 40}{\frac{5}{18} \times (108 + 126)} = 10

    2d+4065=10\frac{2d + 40}{65} = 10
    2d + 40 =650
    d = 305

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