Let the speed of train A and train B be 3x kmph and 2x kmph respectively.
ATQ,
3x-2x=18
x=18
Train A's speed=3×18=54 kmph
Train B's speed=2×18=36 kmph
Let the length of train B be l meters.
(180+l)/(54+36)×18/5=10.8
l=90 m
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