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The volume of a cone with height equal to radius, and slant height 5 cm is :
Question

The volume of a cone with height equal to radius, and slant height 5 cm is :

A.

125π123cm3\frac{125\pi}{12\sqrt3} cm^3​​

B.

125π63cm3\frac{125\pi}{6\sqrt3} cm^3​​

C.

125π122cm3\frac{125\pi}{12\sqrt2} cm^3​​

D.

125π62cm3\frac{125\pi}{6\sqrt2} cm^3​​

Correct option is D

Given:  

Cone height(h) = Cone radius(r) 

Slant height (l) = 5 cm 

Formula Used:

Volume of the cone = 13πr2h\frac13 πr²h 

Slant height = radius2+height2\sqrt{ radius^2 + height^2} 

Solution:  

Let radius r = h = a cm and l = 5 cm

So, 

5=r2+h2 25=(a)2+(a)2 2a2=25  a=525 = \sqrt{r^2 + h^2} \\ \ \\ 25 = (a)^2 + (a)^2 \\ \ \\ 2a^2 = 25 \\ \ \\ \implies a = \frac{5}{\sqrt{2}}​ 
Now, 

Volume of the cone = 13×π×(52)2×52\frac 13 \times \pi \times \left(\frac{5}{\sqrt2}\right)^2 \times \frac 5{\sqrt2}  

13×π×252×52\frac13\times \pi \times \frac{25}{2}\times \frac5{\sqrt2}  

125π62cm3\frac{125 \pi}{6\sqrt2} cm^3​​

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