The values of the mode and the mean are 7.52 and 9.83 respectively in a moderately asymmetrical distribution. Find the median of the distribution.

Correct option is D

Given:

Mode = 7.52

Mean = 9.83

Concept Used:

​$$\text{Mean} - \text{Mode} = 3 \times (\text{Mean} - \text{Median})$$​​

Solution:​

​$$9.83 - 7.52 = 3 \times (9.83 - \text{Median})$$​​

​$$2.31 = 3 \times (9.83 - \text{Median})$$​​

​$$\frac{2.31}{3} = 9.83$$​ - Median

0.77 = 9.83 - Median

Median = 9.83 - 0.77 = 9.06