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    If x and y are upper limit of median class and lower limit of modal class, respectively in the following distribution, then what is the value of (2x +
    Question

    If x and y are upper limit of median class and lower limit of modal class, respectively in the following distribution, then what is the value of (2x + y)?

    A.

    130

    B.

    140

    C.

    150

    D.

    120

    Correct option is A

    Given :  Cumulative frequencies : 3, 22, 35, 47, 55, 80  Formula Used :  N=Total frequency  Median position=N2  Solution :  N=80  N2=40  Median class=30 ⁣ ⁣40  x=40  Class frequencies:  0 ⁣ ⁣10=3  10 ⁣ ⁣20=19  20 ⁣ ⁣30=13  30 ⁣ ⁣40=12  40 ⁣ ⁣50=8  50 ⁣ ⁣60=25  Modal class=50 ⁣ ⁣60  y=50  2x+y=2(40)+50=130  Final Answer :  130\textbf{Given :} \\\ \, \\\text{Cumulative frequencies : } 3,\ 22,\ 35,\ 47,\ 55,\ 80 \\\ \, \\\textbf{Formula Used :} \\\ \, \\N = \text{Total frequency} \\\ \, \\\text{Median position} = \frac{N}{2} \\\ \, \\\textbf{Solution :} \\\ \, \\N = 80 \\\ \, \\\frac{N}{2} = 40 \\\ \, \\\text{Median class} = 30\!-\!40 \\\ \, \\x = 40 \\\ \, \\\text{Class frequencies:} \\\ \, \\0\!-\!10 = 3 \\\ \, \\10\!-\!20 = 19 \\\ \, \\20\!-\!30 = 13 \\\ \, \\30\!-\!40 = 12 \\\ \, \\40\!-\!50 = 8 \\\ \, \\50\!-\!60 = 25 \\\ \, \\\text{Modal class} = 50\!-\!60 \\\ \, \\y = 50 \\\ \, \\2x + y = 2(40) + 50 = 130 \\\ \, \\\textbf{Final Answer :} \\\ \, \\130​​

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