The median of the observations 6, 48, 32, 3, 37 and 18 is:

Correct option is C

​$$\textbf{Given:} \\\text{Observations are } 6,\ 48,\ 32,\ 3,\ 37,\ 18\\\textbf{Formula Used:} \\\text{For an even number of observations,} \\\text{Median} = \dfrac{\text{(n/2)th term + (n/2 + 1)th term}}{2}\\\textbf{Solution:} \\\text{First arrange the observations in ascending order:} \\3,\ 6,\ 18,\ 32,\ 37,\ 48 \\n = 6 \ (\text{even}) \\\text{Median} = \dfrac{\text{3rd term + 4th term}}{2} \\\text{Median} = \dfrac{18 + 32}{2} \\\text{Median} = \dfrac{50}{2} = 25$$​​