The value of sin1° sin2° sin3°...sin180°...sin196° is:

Correct option is C

Given:

​$$\sin(1^\circ) \times \sin(2^\circ) \times \sin(3^\circ) \times \dots \times \sin(180^\circ) \times \dots \times \sin(196^\circ)$$​​

Solution:
In this product, we have $$\sin(180^\circ),$$​ and we know that:

​$$\sin(180^\circ) = 0$$​

Since one of the terms in the product is zero, the entire product becomes zero.