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Simplify: cosecθ(1 – cosθ)(cosecθ + cotθ)
Question

Simplify: cosecθ(1 – cosθ)(cosecθ + cotθ)

A.

–1

B.

sinθ

C.

cosθ

D.

1

Correct option is D

​Given:Expression =cosec⁡θ(1−cos⁡θ)(cosec⁡θ+cot⁡θ)textbfFormulaUsed:cosec⁡θ=1sin⁡θ,cot⁡θ=cos⁡θsin⁡θ1−cos⁡θ=(1−cos⁡θ)(1+cos⁡θ)1+cos⁡θ=1−cos⁡2θ1+cos⁡θ=sin⁡2θ1+cos⁡θSolution:cosec⁡θ(1−cos⁡θ)(cosec⁡θ+cot⁡θ)=1sin⁡θ(1−cos⁡θ)(1sin⁡θ+cos⁡θsin⁡θ)=1sin⁡θ(1−cos⁡θ)(1+cos⁡θsin⁡θ)=(1−cos⁡θ)(1+cos⁡θ)sin⁡2θ=1−cos⁡2θsin⁡2θ=sin⁡2θsin⁡2θ=1\textbf{Given:} \\\text{Expression } = \cosec\theta (1 - \cos\theta)(\cosec\theta + \cot\theta) \\\\textbf{Formula Used:} \\\cosec\theta = \dfrac{1}{\sin\theta}, \quad\cot\theta = \dfrac{\cos\theta}{\sin\theta} \\1 - \cos\theta = \dfrac{(1 - \cos\theta)(1 + \cos\theta)}{1 + \cos\theta}= \dfrac{1 - \cos^2\theta}{1 + \cos\theta}= \dfrac{\sin^2\theta}{1 + \cos\theta}\\\textbf{Solution:} \\\cosec\theta (1 - \cos\theta)(\cosec\theta + \cot\theta) \\= \dfrac{1}{\sin\theta} (1 - \cos\theta)\left( \dfrac{1}{\sin\theta} + \dfrac{\cos\theta}{\sin\theta} \right) \\= \dfrac{1}{\sin\theta} (1 - \cos\theta)\left( \dfrac{1 + \cos\theta}{\sin\theta} \right) \\= \dfrac{(1 - \cos\theta)(1 + \cos\theta)}{\sin^2\theta} \\= \dfrac{1 - \cos^2\theta}{\sin^2\theta} \\= \dfrac{\sin^2\theta}{\sin^2\theta} \\= 1​​

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