​Find the value of $$\frac{1 - \sec^2 \theta}{\sin^2 \theta} \times \cos^2 \theta$$​​​

Correct option is C

Given: ​

​$$\frac{1 - \sec^2 \theta}{\sin^2 \theta} \times \cos^2 \theta$$ 

Formula Used: 

​$$\sec^2 \theta = 1 + \tan^2 \theta$$​​

​$$\frac{\cos \theta}{\sin \theta} = \cot \theta$$ 

Solution: 

$$\frac{1 - \sec^2 \theta}{\sin^2 \theta} \times \cos^2 \theta \\ \ \\ = (- \tan^2 \theta )\times \frac{1}{\tan^2 \theta} \\ \ \\ = -1$$​​