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    ​The value of 3+tan⁡2ϕ+cot⁡2ϕ−sec⁡2ϕcosec⁡2ϕ is:\text{The value of } 3 + \tan^2 \phi + \cot^2 \phi - \sec^2 \phi \cosec^2 \phi \te
    Question

    The value of 3+tan2ϕ+cot2ϕsec2ϕcosec2ϕ is:\text{The value of } 3 + \tan^2 \phi + \cot^2 \phi - \sec^2 \phi \cosec^2 \phi \text{ is:}

    A.

    1

    B.

    2

    C.

    -1

    D.

    0

    Correct option is A

    Given:

    Expression: 3 +tan2ϕ+cot2ϕsec2ϕcosec2ϕ \tan^2 \phi + \cot^2 \phi - \sec^2 \phi \cosec^2 \phi​​

    Formula Used:

    sec2ϕ=1+tan2ϕ cosec2ϕ=1+cot2ϕ \sec^2 \phi = 1 + \tan^2 \phi \\ \ \\\cosec^2 \phi = 1 + \cot^2 \phi

    Solution:

    3+tan2ϕ+cot2ϕ(1+tan2ϕ)(1+cot2ϕ)3 + \tan^2 \phi + \cot^2 \phi - (1 + \tan^2 \phi)(1 + \cot^2 \phi)​​

    =3+tan2ϕ+cot2ϕ(1+tan2ϕ+cot2ϕ+tan2ϕcot2ϕ)= 3 + \tan^2 \phi + \cot^2 \phi - (1 + \tan^2 \phi + \cot^2 \phi + \tan^2 \phi \cot^2 \phi)​​

    =31tan2ϕcot2ϕ 3 - 1 - \tan^2 \phi \cot^2 \phi​​

    Since tanϕcotϕ=1,tan2ϕcot2ϕ=1\tan \phi \cot \phi = 1, \tan^2 \phi \cot^2 \phi = 1​, so the expression becomes:

    = 2 - 1 = 1

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