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​The value of 3+tan⁡2ϕ+cot⁡2ϕ−sec⁡2ϕcosec⁡2ϕ is:\text{The value of } 3 + \tan^2 \phi + \cot^2 \phi - \sec^2 \phi \cosec^2 \phi \te
Question

The value of 3+tan2ϕ+cot2ϕsec2ϕcosec2ϕ is:\text{The value of } 3 + \tan^2 \phi + \cot^2 \phi - \sec^2 \phi \cosec^2 \phi \text{ is:}

A.

1

B.

2

C.

-1

D.

0

Correct option is A

Given:

Expression: 3 +tan2ϕ+cot2ϕsec2ϕcosec2ϕ \tan^2 \phi + \cot^2 \phi - \sec^2 \phi \cosec^2 \phi​​

Formula Used:

sec2ϕ=1+tan2ϕ cosec2ϕ=1+cot2ϕ \sec^2 \phi = 1 + \tan^2 \phi \\ \ \\\cosec^2 \phi = 1 + \cot^2 \phi

Solution:

3+tan2ϕ+cot2ϕ(1+tan2ϕ)(1+cot2ϕ)3 + \tan^2 \phi + \cot^2 \phi - (1 + \tan^2 \phi)(1 + \cot^2 \phi)​​

=3+tan2ϕ+cot2ϕ(1+tan2ϕ+cot2ϕ+tan2ϕcot2ϕ)= 3 + \tan^2 \phi + \cot^2 \phi - (1 + \tan^2 \phi + \cot^2 \phi + \tan^2 \phi \cot^2 \phi)​​

=31tan2ϕcot2ϕ 3 - 1 - \tan^2 \phi \cot^2 \phi​​

Since tanϕcotϕ=1,tan2ϕcot2ϕ=1\tan \phi \cot \phi = 1, \tan^2 \phi \cot^2 \phi = 1​, so the expression becomes:

= 2 - 1 = 1

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