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The sum of two numbers is 35. Their product is 150. Find the HCF of the sum of their reciprocals and the difference of the reciprocals.
Question

The sum of two numbers is 35. Their product is 150. Find the HCF of the sum of their reciprocals and the difference of the reciprocals.

A.

7/15

B.

1/30

C.

7/30

D.

5/30

Correct option is B

Formula Used:
(x+y)2(xy)2=4xy(x + y)^2 - (x - y)^2 = 4xy​​​
Solution:
Let first number =x
Let second number =y
x+y=35 
​x×y=150
The sum of the reciprocals of xxx and yyy is
x+yx×y=35150=730\frac{x + y}{x \times y} = \frac{35}{150} = \frac{7}{30}  
difference between number x-y =d
(x+y)2(xy)2=4xy(x + y)^2 - (x - y)^2 = 4xy​​
352d2=4×15035^2 - d^2 = 4 \times 150 
d=25d = 25   
The difference  of the reciprocals ofxxxandyyyis​
1x1y=xyx×y\frac{1}{x} - \frac{1}{y} = \frac{x - y}{x \times y} 
=25/150
=1/6 
So hcf of  7/30 and 1/6 is 1/30
​​​

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