Correct option is D
Given:
Concept Used:
Each term in the series can be rewritten as:
Solution:
=
That most terms cancel out:
=
=
=
= 0.16
Thus, the correct answer is (d).
The sum of the first 20 terms of the series is:
Given:
Concept Used:
Each term in the series can be rewritten as:
Solution:
=
That most terms cancel out:
=
=
=
= 0.16
Thus, the correct answer is (d).
12 numbers are in arithmetic progression. Average of first and last number of this progression is 16. What is the average of these 12 numbers?
6 + 12 + 18 + 24 + ....... +612 = ?
All pillars of street light was installed in a straight line at a distance of 50 meter(m) interval. What will be the distance between first and ninth pillar ?
Find the sum of all three-digit numbers divisible by 9 .
Next number in the series 1, 50, 100, 5000, 10000, ___ is :
On simplification, 1 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + _____+ 111, we get
The sum of 21 + 22 + 23 + .....+ 50 is
1 + 2 + 3 +………+ 50 equals
On simplification 1 – 2 + 3 – 4 + 5 – 6 - - - - + 101, we get
If 12 + 22 + …. + 92 = 285, then the value of (0.11)2 + (0.22)2 + … + (0.99)2 is -
Suggested Test Series
Suggested Test Series
12 numbers are in arithmetic progression. Average of first and last number of this progression is 16. What is the average of these 12 numbers?
6 + 12 + 18 + 24 + ....... +612 = ?
All pillars of street light was installed in a straight line at a distance of 50 meter(m) interval. What will be the distance between first and ninth pillar ?
Find the sum of all three-digit numbers divisible by 9 .
Next number in the series 1, 50, 100, 5000, 10000, ___ is :
On simplification, 1 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + _____+ 111, we get
The sum of 21 + 22 + 23 + .....+ 50 is
1 + 2 + 3 +………+ 50 equals
On simplification 1 – 2 + 3 – 4 + 5 – 6 - - - - + 101, we get
If 12 + 22 + …. + 92 = 285, then the value of (0.11)2 + (0.22)2 + … + (0.99)2 is -