All pillars of street light was installed in a straight line at a distance of 50 meter(m) interval. What will be the distance between first and ninth pillar ?
Given:
Distance between two adjacent pillars = 50 m
Number of pillars = 9
Formula Used:
Total Distance = (Number of pillars - 1) × Distance between adjacent pillars
Solution:
The number of intervals between the 9 pillars is calculated by subtracting 1 from the total number of pillars.
Intervals = 9 - 1 = 8
Total distance = 8 × 50 = 400 m
Final Answer
So the correct answer is (d)
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120 Mins English English100 Questions100 Marks120 Mins English English25 Questions100 Marks20 Mins English12 numbers are in arithmetic progression. Average of first and last number of this progression is 16. What is the average of these 12 numbers?
6 + 12 + 18 + 24 + ....... +612 = ?
All pillars of street light was installed in a straight line at a distance of 50 meter(m) interval. What will be the distance between first and ninth pillar ?
Find the sum of all three-digit numbers divisible by 9 .
On simplification 1 – 2 + 3 – 4 + 5 – 6 - - - - + 101, we get
1 + 2 + 3 +………+ 50 equals
If in an A.P., the pᵗʰ term is q and the (p + q)ᵗʰ term is 0, then the qᵗʰ term is:
If in an A.P., Sₙ = qn² and Sₘ = qm², where Sᵣ denotes the sum of first r terms of the A.P., then equals:
The first term and last term of an AP are 33 and -57 respectively. If there are 16 terms in the series, then what will be sum?
Sum of p terms of AP is q and sum of q terms of AP is p. Common difference of A.P. is:
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