12 numbers are in arithmetic progression. Average of first and last number of this progression is 16. What is the average of these 12 numbers?

Correct option is B

Given:
Total numbers in Arithmetic Progression (AP) = 12
Average of the first and last number = 16
Formula Used:
Average of an AP = $$\frac{First\ term + Last\ term}{2}$$​​
Solution:
In any Arithmetic Progression, the average of all the terms in the sequence is equal to the average of its first and last terms.
Given that the average of the first and last term is 16:
$$\frac{a + l}{2}$$​ = 16
Since the average of the entire sequence is the same as the average of the extreme terms, the average of all 12 numbers must also be 16.
Final Answer
So the correct answer is (b)