12 numbers are in arithmetic progression. Average of first and last number of this progression is 16. What is the average of these 12 numbers?

12 numbers are in arithmetic progression. Average of first and last number of this progression is 16. What is the average of these 12 numbers?

6 + 12 + 18 + 24 + ....... +612 = ?

All pillars of street light was installed in a straight line at a distance of 50 meter(m) interval. What will be the distance between first and ninth pillar ?

Find the sum of all three-digit numbers divisible by 9 .

On simplification 1 – 2 + 3 – 4 + 5 – 6 - - - - + 101, we get

1 + 2 + 3 +………+ 50 equals

If in an A.P., the pᵗʰ term is q and the (p + q)ᵗʰ term is 0, then the qᵗʰ term is:

If in an A.P., Sₙ = qn² and Sₘ = qm², where Sᵣ denotes the sum of first r terms of the A.P., then $$S_q$$​ equals:

The first term and last term of an AP are 33 and -57 respectively. If there are 16 terms in the series, then what will be sum?

Sum of p terms of AP is q and sum of q terms of AP is p. Common difference of A.P. is: