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If 12 + 22 + …. + 92 = 285, then the value of (0.11)2 + (0.22)2 + … + (0.99)2 is -
Question

If 12 + 22 + …. + 92 = 285, then the value of (0.11)2 + (0.22)2 + … + (0.99)2 is -

A.

2.4485

B.

0.24485

C.

3.4485

D.

0.34485

Correct option is C

Given:

1² + 2² + … + 9² = 285

Need to find: (0.11)² + (0.22)² + … + (0.99)²

Formula used:
If a number is multiplied by 0.11, its square becomes:
(0.11n)² = 0.0121 × n²

Solution:

We can write:
(0.11)² + (0.22)² + … + (0.99)²
= 0.0121 × (1² + 2² + … + 9²)
= 0.0121 × 285
= 3.4485

Correct answer is (c) 3.4485.

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