The sides of a rectangle are 49 m and 35 m respectively. How many square beds can be accommodated in this rectangle if the side of the bed is 7 m?

Correct option is D

Given:

The sides of the rectangle are 49 m and 35 m

The side of each square bed is 7 m.
Formula Used:

Area of rectangle = length \times breadth

Solution:
The area of the rectangle :
Area of rectangle= $$49 \times 35 = 1715 meters^2$$​​
The area of one square bed is:
Area of bed =$$7 \times 7 = 49 meters^2$$​​
​$$\frac{1715}{49} = 35$$​​
Thus, 35 square beds can be accommodated in the rectangle.