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    The sides of a rectangle are 49 m and 35 m respectively. How many square beds can be accommodated in this rectangle if the side of the bed is 7 m?
    Question

    The sides of a rectangle are 49 m and 35 m respectively. How many square beds can be accommodated in this rectangle if the side of the bed is 7 m?

    A.

    36

    B.

    33

    C.

    34

    D.

    35

    Correct option is D

    Given:

    The sides of the rectangle are 49 m and 35 m

    The side of each square bed is 7 m.
    Formula Used:

    Area of rectangle = length \times breadth

    Solution:
    The area of the rectangle :
    Area of rectangle= 49×35=1715meters249 \times 35 = 1715 meters^2​​
    The area of one square bed is:
    Area of bed =7×7=49meters2 7 \times 7 = 49 meters^2​​
    171549=35\frac{1715}{49} = 35​​
    Thus, 35 square beds can be accommodated in the rectangle.

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