The receiving end voltage of a radial distribution network is 24 kV. What will be the sending end voltage, if the voltage drop is calculated 25% of receiving end voltage?

Correct option is D

$$\text{Given:} \\[4pt]\bullet \; \text{Receiving end voltage } V_R = 24\,\text{kV} \\[4pt]\bullet \; \text{Voltage drop } = 25\% \text{ of } V_R \\[8pt]\text{Voltage drop } = 0.25 \times V_R \\[6pt]V_S = V_R + \text{Voltage drop} \\[6pt]\text{Voltage drop } = 0.25 \times 24 = 6\,\text{kV} \\[8pt]\text{Sending end voltage } V_S = 24 + 6 = 30\,\text{kV}$$​​