In a dc two wire feeder the voltage drop per wire is 3%. Transmission efficiency of the feeder is:

Correct option is A

​$$\text{In a DC two-wire feeder:} \\[8pt]\bullet \ \text{Voltage drop in each wire } = 3\% \\[6pt]\bullet \ \text{Since there are two wires, the total voltage drop is:} \\[8pt]3\% + 3\% = 6\% \\[14pt]\text{Transmission efficiency is given by:} \\[8pt]\text{Efficiency} = \frac{\text{Receiving-end voltage}}{\text{Sending-end voltage}} \times 100 \\[10pt]= (100\% - \text{Total voltage drop}) \\[10pt]= 100\% - 6\% = 94\%$$​​