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    The population of a small city decreased every year due to water contamination. The present population of the town is 1,39,650. Last year, the mi
    Question

    The population of a small city decreased every year due to water contamination. The present population of the town is 1,39,650. Last year, the migration was 2%, and the year before last, it was 5%. What was the population of the city two years ago?

    A.

    1,45,000

    B.

    1,50,000

    C.

    1,55,000

    D.

    1,25,000

    Correct option is B

    Given:

    Present population = 1,39,650

    Migration last year = 2%

    Migration year before last = 5%

    Formula used:

    Population after decrease = Previous population × (1 - Decrease rate)

    Solutions:

    Let the population two years ago be P.

    Population after 1st year decrease = P × (15100)\left(1 -\frac 5{100}\right)​​

    Population after 1st year = P × 0.95

    Population after 2nd year decrease = (P × 0.95) × (12100)\left(1 -\frac 2{100}\right)​​

    Population after 2nd year = P × 0.95 × 0.98

    We know that population after 2nd year = 1,39,650.

    1,39,650 = P × 0.95 × 0.98

    P = 1,39,650(0.95×0.98)\frac{1,39,650 }{ (0.95 × 0.98)} 

    P = 1, 50 ,000

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