The population of a district is 385000, out of which 168000 are males. 52% of the population is literate. If 21% males are literate, then what percentage of females are literate?

Correct option is C

Given:

Total population = 385000

Number of males = 168000

Percentage of literates = 52% of 385000

Percentage of literate males = 21% of 168000

Formula Used:

Female Literacy % = $$\left( \frac{\text{Literate Females}}{217000} \right) \times 100$$​

Solution:

Total literates = $$\frac{52}{100} \times 385000$$​ = 200200 

Literate males = $$\frac{21}{100} \times 168000$$​ = 35280 

Literate females = 200200 - 35280 = 164920

Female population = 385000 - 168000 = 217000

Female literacy % = $$\frac{164920}{217000} \times 100 \approx 76\%$$​​