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    The population of a district is 384000, out of which 192000 are males. 69% of the population is literate. If 53% males are literate, then what percent
    Question

    The population of a district is 384000, out of which 192000 are males. 69% of the population is literate. If 53% males are literate, then what percentage of females are literate?

    A.

    84%

    B.

    87%

    C.

    85%

    D.

    82%

    Correct option is C

    Given:
    Total population = 384,000
    Number of males = 192,000
    Percentage of literate population = 69%
    Percentage of literate males = 53%
    Formula Used:
    Total literate population = Literate males + Literate females
    Total population×Total literacy %=Male population×Male literacy %+Female population×Female literacy %\text{Total population} \times \text{Total literacy \%} = \text{Male population} \times \text{Male literacy \%} + \text{Female population} \times \text{Female literacy \%} ​​
    Female literacy %=Total literateLiterate malesFemale population×100 \text{Female literacy \%} = \frac{\text{Total literate} - \text{Literate males}}{\text{Female population}} \times 100 ​​
    Solution:
    Number of females  = Total population - Number of males = 384000 -192000 = 192000
    Total literate population=384,000×69100=264,960Literate males=192,000×53100=101,760Literate females=264,960101,760=163,200Percentage of literate females=163,200192,000×100=85% \text{Total literate population} = 384,000 \times \frac{69}{100} = 264,960 \\ \text{Literate males} = 192,000 \times \frac{53}{100} = 101,760 \\ \text{Literate females} = 264,960 - 101,760 = 163,200 \\ \text{Percentage of literate females} = \frac{163,200}{192,000} \times 100 = 85\% \\​​
    85% of the females are literate.

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