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The lengths of each side of two squares are given as (5 + √ 3) cm and (5 - √ 3) cm, respectively. What is the sum of the areas of these two square?
Question

The lengths of each side of two squares are given as (5 + √ 3) cm and (5 - √ 3) cm, respectively. What is the sum of the areas of these two square?

A.

56 cm2

B.

28 cm2

C.

25 cm2

D.

52 cm2

Correct option is A

Given:
Side of first square = 5+35 + \sqrt{3}​​
Side of second square = 535 - \sqrt{3}​​
Formula Used:
Area of square = (Side)2 (Side)^2​​
(a+b)2+(ab)2=2(a2+b2)(a + b)^2 + (a - b)^2 = 2(a^2 + b^2)​​
Solution:
Area of the first square = (5+3)2 (5 + \sqrt{3})^2​​
Area of the second square = (53)2(5 - \sqrt{3})^2​​
Sum of areas = (5+3)2+(53)2 (5 + \sqrt{3})^2 + (5 - \sqrt{3})^2​​
Applying the algebraic identity.
Sum = 2((5)2+(3)2) 2((5)^2 + (\sqrt{3})^2)​​
Sum = 2(25 + 3)
Sum = 2 × 28 = 56
Final Answer
So the correct answer is (a)

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