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The lengths of each side of two squares are given as 5 + √ 3 cm and 5 - √ 3 cm, respectively. What is the sum of the areas of these two square?
Question

The lengths of each side of two squares are given as 5 + √ 3 cm and 5 - √ 3 cm, respectively. What is the sum of the areas of these two square?

A.

56 cm2

B.

28 cm2

C.

25 cm2

D.

52 cm2

Correct option is A

Given:
Side of the first square = 5+35 + \sqrt{3}​ cm
Side of the second square = 535 - \sqrt{3}​ cm
Formula Used:
Area of a square = Side2
Algebraic identity: (a+b)2+(ab)2=2(a2+b2)(a + b)^2 + (a - b)^2 = 2(a^2 + b^2)​​
Solution:
Area of the first square = (5+3)2(5 + \sqrt{3})^2​​
Area of the second square = (53)2(5 - \sqrt{3})^2​​
Sum of the areas = (5+3)2+(53)2(5 + \sqrt{3})^2 + (5 - \sqrt{3})^2​​
Using the algebraic identity where a = 5 and b = 3:\sqrt{3}:​​
Sum = 2(52+(3)2)2(5^2 + (\sqrt{3})^2)​​
Sum = 2(25 + 3)
Sum = 2(28)
Sum = 56
Final Answer
So the correct answer is (a)

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