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The largest number which divides 55, 72 and 123 leaving the remainders 3, 7 and 6 respectively is:
Question

The largest number which divides 55, 72 and 123 leaving the remainders 3, 7 and 6 respectively is:

A.

13

B.

117

C.

66

D.

26

Correct option is A

Given:

Numbers = 55, 72, 123

Remainders = 3, 7, 6

Concept used:

H.C.F  is the largest number which divides all number completely.

Solution:

55 - 3 = 52

72 - 7 = 65

123 - 6 = 117

H.C.F of 52, 65, 117

=> 52 = 13 × 2× 2

=> 65 = 13 × 5

=> 117 = 13 × 3× 3× 3

So H.C.F = 13

So, 13 is the largest number which divides all number completely.



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