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    The largest number which divides 55, 72 and 123 leaving the remainders 3, 7 and 6 respectively is:
    Question

    The largest number which divides 55, 72 and 123 leaving the remainders 3, 7 and 6 respectively is:

    A.

    13

    B.

    117

    C.

    66

    D.

    26

    Correct option is A

    Given:

    Numbers = 55, 72, 123

    Remainders = 3, 7, 6

    Concept used:

    H.C.F  is the largest number which divides all number completely.

    Solution:

    55 - 3 = 52

    72 - 7 = 65

    123 - 6 = 117

    H.C.F of 52, 65, 117

    => 52 = 13 × 2× 2

    => 65 = 13 × 5

    => 117 = 13 × 3× 3× 3

    So H.C.F = 13

    So, 13 is the largest number which divides all number completely.



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