The HCF of 36, 48 and 172 is _______.

Correct option is A

Given:

Numbers = 36, 48, 172

We need HCF (36, 48, 172).

Solution:

Prime factorization

36 = $$2^2 \times 3^2$$​​

48 =$$2^4 \times 3$$​​

172 $$= 2^2 \times 43$$​​

Take common factors

Common prime factor among all three =$$2^2 = 4$$​​

So,

HCF(36, 48, 172) = 4