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    The distance between two stations, Delhi and Amritsar is 450 km. A train starts at 4 p.m. from Delhi and moves towards Amritsar at an average speed of
    Question

    The distance between two stations, Delhi and Amritsar is 450 km. A train starts at 4 p.m. from Delhi and moves towards Amritsar at an average speed of 60 km/h. Another train starts from Amritsar at 3 : 20 p.m. and moves towards Delhi at an average speed of 80 km/h. At what distance from Delhi will the two trains meet?

    A.

    170km

    B.

    180km

    C.

    160km

    D.

    165km

    Correct option is A

    Given:

    Distance between Delhi and Amritsar = 450km

    Train A starts from Delhi at 4:00p.m. at 60km/hr

    Train B starts from Amritsar at 3:20p.m. at 80km/hr

    Formula Used:

    Time = DistanceSpeed\frac{Distance}{Speed}​​

    Distance = Speed ×\times​ Time

    Solution:

    Train B leaves early at 3:20pm hence distance travelled by train B in till 4:00pm will be:

    Time = 40min =4060=23hr \frac{40}{60} = \frac{2}{3}hr​​

    Distance = 80×23=1603km80 \times \frac{2}{3} = \frac{160}{3}km​​

    Distance left =4501603=13501603=11903km 450 - \frac{160}{3} = \frac{1350- 160}{3} = \frac{1190}{3}km​​

    Now at 4:00pm train A starts moving towars train B hence

    Relative speed of both trains = 60 + 80 = 140 km/hr

    Now time taken to cover the distance =11903140=176=256hr \frac{\frac{1190}{3}}{140}= \frac{17}{6}= 2\frac{5}{6}hr

    Distance covered by train A in 256hr=60×176=170km 2\frac{5}{6}hr = 60 \times \frac{17}{6} =170km​​

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