The distance between two places is 100 km. A and B start walking towards each other at the same time and meet each other after 4 hours. If A travelled with double of his speed while B travelled with 2/3rd of his speed, they would have met after 3 hours 20 minutes. What is the speed of A?

Correct option is C

Given: The distance between two places is 100 km.
The meet after 4 hours.
Formula Used: Distance = Speed × Time
Calculation: Let the speed of A be x. Let the speed of B be y.
According to the question: ⇒ 100/(x + y) = 4
x + y = 25
y = 25 - x
The new speed of A = 2x
The new speed of B = 2y/3
100/(2x + 2y/3) = 10/3
2x + 2y/3 = 30
2x + 2(25 - x)/3 = 30
6x + 50 - 2x = 90
4x = 40
x = 10 km/hr
The speed of A is 10 km/hr.