The average of 6 numbers is 28. The average of first two numbers is 26 and the last two is 32. Find the average of the remaining two numbers

Correct option is A

Given:

The average of 6 numbers = 28

The average of the first two numbers = 26

The average of the last two numbers = 32

Formula Used:

Sum of numbers = Average × Total number of terms

Solution:

Sum of 6 numbers = 28 × 6 = 168

Sum of first two numbers = 26 × 2 = 52

Sum of last two numbers = 32 × 2 = 64

Sum of remaining two numbers = 168 − (52 + 64) = 168 − 116 = 52

Average of remaining two numbers = $$\frac{52}{2}$$​ = 26