The average of 19 consecutive natural numbers is 41. What is the smallest number among these numbers?

Correct option is B

Given:

Average of 19 consecutive natural numbers = 41

We are to find the smallest number among them.

Concept Used:

For an odd number of consecutive terms, the average is equal to the middle term.

Formula Used:

Smallest = $$\text{Average} - \left(\frac{n - 1}{2}\right)$$​​

Solution: 

Middle term = 41

Total numbers = 19

Thus, 

Smallest = 41 - $$\frac{19 - 1}{2}$$​ = 41 - 9 = 32