The average age of A, B and C is 20 years. Two years ago, the sum of the ages of A and B was 6 more than that of C. Find the present age of C.

Average age of A, B and C = 20 years

Average: The average of a group of numbers is the sum of the numbers divided by the number of elements in the group.

Algebraic Equations: Formulating and solving equations based on the given conditions.

As per the question;

Average age of A, B and C = 20 years

Sum of present ages of A, B and C = 20 × 3 = 60 years

Sum of ages of A, B and C, 2 years ago = 60 – 2 × 3 = 54 years

2 years Ago, sum of ages of A and B is 6 years more than that of C.

Now, age of C before 2 years = (54 - 6)/2 = 24 years

So,

Present age of C = 24 + 2 = 26 years.