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    The arithmetic mean of 25 real numbers is 110. If 10 numbers are increased by 121212\frac{1}{2}1221​ each, another 10 numbers are increased
    Question

    The arithmetic mean of 25 real numbers is 110. If 10 numbers are increased by 121212\frac{1}{2} each, another 10 numbers are increased by 15 each and the remaining 5 numbers are unaltered, then the new value of the arithmetic mean is:​

    A.

    125

    B.

    121

    C.

    120

    D.

    112

    Correct option is B

    Given:

    Mean of 25 numbers = 110

    Original total = 25×110=2750. \times 110 = 2750.​​

    10 numbers increased by 1212=12.2\frac{1}{2} = 12.​5 each.

    Another 10 numbers increased by 15 each.

    Remaining 5 numbers unchanged.

    Formula Used:

    New mean =New totalNumber of items= \dfrac{\text{New total}}{\text{Number of items}}​​

    Solution:
    Total increment =10×12.5+10×15=125+150=275 10 \times 12.5 + 10 \times 15 = 125 + 150 = 275​​
    New total = 2750 + 275 = 3025.
    New mean =302525=12 \dfrac{3025}{25} = 12​1.

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