Simplify: cos θ(1 - tan θ) + sin θ (1 - cot θ)

Given:cos⁡θ(1−tan⁡θ)=cos⁡θ−cos⁡θtan⁡θ \\cos \\theta(1 - \\tan \\theta) = \\cos \\theta - \\cos \\theta \\tan \\theta cosθ(1−tanθ)=cosθ−cosθtanθ sin⁡θ(1−cot⁡θ)=sin⁡θ−sin⁡θcot⁡θ\\sin \\theta(1 - \\cot \\theta) = \\sin \\theta - \\sin \\theta \\cot \\theta sinθ(1−cotθ)=sinθ−sinθcotθUse the trigonometric identities:tan⁡θ=sin⁡θcos⁡θ and cot⁡θ=cos⁡θsin⁡θ:\\tan \\theta = $$\\frac{\\sin \\theta}{\\cos \\theta}$$ $$\\text{ and }$$ \\cot \\theta = $$\\frac{\\cos \\theta}{\\sin \\theta}$$: \\\\tanθ=cosθsinθ and cotθ=sinθcosθ:cos⁡θ⋅tan⁡θ=sin⁡θsin⁡θ⋅cot⁡θ=cos⁡θ\\cos \\theta \\cdot \\tan \\theta = \\sin \\theta \\\\\\sin \\theta \\cdot \\cot \\theta = \\cos \\thetacosθ⋅tanθ=sinθsinθ⋅cotθ=cosθthen the value of = cos θ(1 - tan θ) + sin θ (1 - cot θ)cos⁡θ−cos⁡θtan⁡θ\\cos \\theta - \\cos \\theta \\tan \\theta cosθ−cosθtanθ + sin⁡θ−sin⁡θcot⁡θ \\sin \\theta - \\sin \\theta \\cot \\theta sinθ−sinθcotθcos⁡θ−sin⁡θ+sin⁡θ−cos⁡θ=0\\cos \\theta - \\sin \\theta + \\sin \\theta - \\cos \\theta = 0cosθ−sinθ+sinθ−cosθ=0Final Answer: The simplified expression is 0.